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EIGRP Questions 10

May 5th, 2014 in ROUTE 642-902 Go to comments

Here you will find answers to EIGRP questions – Part 10

Question 1

Refer to the exhibit. Network administrators have set up a hub and spoke topology with redundant connections using EIGRP. However, they are concerned that a network outage between Router R1 and Router R2 will cause traffic from the 10.1.1.x network to the 10.1.2.x network to traverse the remote office links and overwhelm them. What command should be used to configure the spoke routers as EIGRP stub routers that will not advertise connected networks, static routes, or summary addresses?


A. eigrp stub
B. eigrp stub receive-only
C. eigrp stub connected static
D. no eigrp stub connected static
E. No additional command is needed beyond a default EIGRP configuration.


Answer: B

Question 2

A network administrator is troubleshooting an EIGRP connection between RouterA, IP address, and RouterB, IP address Given the debug output on RouterA, which two statements are true?

RouterA#debug eigrp packets

01:39:13: EIGRP: Received HELLO on Serial0/0 nbr
01:39:13: AS 100, Flags 0x0, Seq idbQ 0/0 iidbQ un/rely 0/0 peerQ un/rely 0/0
01:39:13: K-value mismatch

A. RouterA received a hello packet with mismatched autonomous system numbers.
B. RouterA received a hello packet with mismatched hello timers.
C. RouterA received a hello packet with mismatched authentication parameters.
D. RouterA received a hello packet with mismatched metric-calculation mechanisms.
E. RouterA will form an adjacency with RouterB.
F. RouterA will not form an adjacency with RouterB.


Answer: D F

Question 3

Observe the exhibit. If the command variance 3 were added to RTE, which path or paths would be chosen to route traffic to network X?


A. E-B-A
B. E-B-A and E-C-A
C. E-C-A and E-D-A
D. E-B-A, E-C-A and E-D-A


Answer: B


Please notice that routes must first satisfy the feasible condition to be considered for “variance” command:

The feasible condition states:
“To qualify as a feasible successor, a router must have an AD less than the FD of the current successor route”.

In this case, the current successor route is E -> C -> A and the FD of this successor route is 20. But the AD of route E-D-A is 25 which is bigger than the FD of the successor route -> It will not be put into the routing table even if the “variance 3” command is used.

Question 4

Router E is configured with the EIGRP variance 2 command. What path will Router E take to reach Router A?


A. only E-D-A
B. only E-B-A
C. only E-C-A
D. both E-B-A and E-C-A
E. both E-B-A and E-D-A
F. all available paths.


Answer: D

Question 5

Refer to the exhibit. Which router configuration command can be given that will restrict router RTB from sharing its routing information with router RTA?


A. The eigrp stub command on router RTA.
B. The eigrp stub command on router RTB.
C. The eigrp stub connected command on router RTA
D. The eigrp stub connected command on router RTB
E. The eigrp stub receive-only command on router RTA
F. The eigrp stub receive-only command on router RTB


Answer: F


The receive-only keyword will restrict the router from sharing any of its routes with any other router in that EIGRP autonomous system, and the receive-only keyword will not permit any other option to be specified because it prevents any type of route from being sent. The three other optional keywords (connected, static, and summary) can be used in any combination but cannot be used with the receive-only keyword.

(Reference: http://www.cisco.com/en/US/docs/ios/12_0s/feature/guide/eigrpstb.html)

Question 6

Refer to the exhibit. On all routers in the network, EIGRP has been configured for load balancing across the three links. However, traffic destined for Network B from R1 is only load balanced over paths R1-R2-R5 and R1-R3-R5. What is the cause of the problem?


A. EIGRP will not select more than two links for unequal cost path load balancing.
B. Because the path has a different link type, EIGRP will not select path R1-R4-R5 for load balancing.
C. Because Router R4 is not a feasible successor, EIGRP will not select path R1-R4-R5 for load balancing.
D. EIGRP will not select path R1-R4-R5 for load balancing unless the value of the variance parameter is increased.


Answer: C


The feasible condition states:
“To qualify as a feasible successor, a route must have an AD less than the FD of the current successor route”. In this case the AD of R4 is 25 (to network B, which is larger than the FD of the current successor R2 (its FD is 10 + 10 = 20) -> R4 is not a feasible successor.

Question 7

Refer to the exhibit. Which statement about dynamic routing protocols for this network is true?


A. No dynamic interior routing protocol can summarize as shown.
B. Unless configured otherwise, EIGRP would automatically summarize the prefixes as shown in the exhibit.
C. With this IP addressing scheme, EIGRP can be manually configured to summarize prefixes at the specified summarization points.
D. The IP address design lends itself to OSPF. Each summarizing router would be an ABR, summarizing to the next area in the address hierarchy.


Answer: C

Question 8

Refer to the topology diagram R2 is redistributing the EIGRP routers into OSPF. What will the EIGRP routes appear in the routing table of R1?


A. O
C. O E2
D. D


Answer: C


By default, routes redistributed into OSPF will be considered External route – Type 2 (E2) with the default metric of 20. For E2 route, the cost is only from the ASBR to the final destination.

Question 9

Refer to the Exhibit. Routers in the Diagram are configured with EIGRP. If RB and RC fail, which action will RA take with respect to the HQ network?


A. RA will automatically route packets via RD to the HQ network.
B. RA will place the route via RD into the hold down state.
C. RA will go into the active state for all routes.
D. RA will go into the active state for the route to HQ network.


Answer: D


The cost advertised from RD is too big (100) so it cannot be a feasible successor -> RA will go to the active state if both RB and RC fail.

  1. Ali
    May 9th, 2014

    Q10: why not C?

  2. srndach
    May 11th, 2014

    Where is Q 10 ?

  3. Sayed saad
    May 16th, 2014

    Q8 ? why not D EX ?????

  4. Amao
    May 16th, 2014

    @Sayed, it cannot be D EX, the question was about EIGRP routes redistributed into OSPF. they will be displayed in OSPF routing table as OSPF routes (O) and by default external routes redistributed into OSPF will be redistributed as external type 2. ======O E2

  5. Avinash
    June 18th, 2014

    Hi Ali , this will not go into active for all routes as only HQ routes through RB & RC will be lost and obviously if there are any more routes through them.However, RD and routers in that direction are still available and they may also have a route to the HQ networks though that will not be used due to a bad metric .This can be also be verified by sh ip eigrp topology all-links ?
    I think after the calculation is all over , this will become the successor as there are no other routes to the HQ than the RD router.

  6. Eric
    July 1st, 2014

    The Q9 is clear on what action RA will take with respect to the HQ network.

  7. Ambro
    July 2nd, 2014

    I think the exact point is that route recalculation applies to only the affected route (one without a qualified FS)

    Correct or not ?

  8. young
    August 17th, 2014

    guys anyone who has taken the new CCNP route exam??

  9. Time
    August 18th, 2014

    What kind of new CCNP route? The new exams will be on january 2015 i think.

  10. Mike
    September 26th, 2014

    Regarding Question 6: The route through R4 meet the feasibility condition due to its AD of 25 which is lower than the FD of 30 of R1. Why is R4 is not being consider as one of the FS for load balancing? Can there be only 1 FS for equal load balancing? If the variance 2 command was issued this R4 path would certainly be consider for un-equal load balancing.

  11. maru
    September 27th, 2014

    @mike read again the explanation. 30 is FD of feasable successor through R3 not of successor through R2 which is 20. Should compare 25 to 20 not to 30.

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    December 27th, 2014

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  16. Vannara
    January 2nd, 2015

    Q,9 : i think B is the right choice!

  17. dorjee
    January 4th, 2015

    Can somebody explain why C is the answer for question 6.

  18. Ashley
    January 6th, 2015


    The answer is correct

    Because, for load balancing i..e via Variance, the routes must be feasible successor where its AD must be LESS THAN FD of the best route (sucessor) who has least metric.

    Hence, C

  19. cuda
    January 28th, 2015

    Just passed the ccnp route 902. All questions on tut. All 5 sims on the money. used cbt nuggets and tut. Thanks tut.

  20. ME@here.com
    February 15th, 2015

    3/5/6 : same question.



  21. renato
    March 19th, 2015

    The questions 3 and 4 are wrong?

  22. Anonymous
    May 30th, 2015

    @renato I support you 3 is wrong.Should all routes be in the routing table bcz all are less than 60(20*3)

  23. Anonymous
    May 30th, 2015

    @renato but Q4 is true

  24. Anonymous
    May 11th, 2016

    Q7, why C? Can someone give an explanations? Let’s say B also is correct. EIGRP autosummarizes all prefixes. So why C is more lykely than B?

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