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EIGRP Simlet

May 5th, 2014 in Lab Sim Go to comments

EIGRP – SHOW IP EIGRP TOPOLOGY ALL-LINKS

 

Here you will find answers to EIGRP Simlet question

Question

Refer to the exhibit. BigBids Incorporated is a worldwide auction provider. The network uses EIGRP as its routing protocol throughout the corporation. The network administrator does not understand the convergence of EIGRP. Using the output of the show ip eigrp topology all-links command, answer the administrator’s questions.

simlet_show_ip_eigrp_topology_all_links

Question 1

Which two networks does the Core1 device have feasible successors for? (Choose two)

A – 172.17.0.0/30
B – 172.17.1.0/24
C – 172.17.2.0/24
D – 172.17.3.0/25
E – 172.17.3.128/25
F – 10.140.0.0/24

 

Answer: A F

Explanation

To understand the output of the “show ip eigrp topology all-links command” command, let’s analyze an entry (we choose the second entry because it is better for demonstration than the first one)

FeasibleDistance_and_AdvertisedDistance

The first line tells us there is only 1 successor for the path to 10.140.0.0/24 network but there are 2 lines below. So we can deduce that one line is used for successor and the other is used for another route to that network. Each of these two lines has 2 parameters: the first one (“156160” or “157720”) is the Feasible Distance (FD) and the second (“128256” or “155160”) is the Advertised Distance (AD) of that route.

The next thing we want to know is: if the route via 172.17.10.2 (the last line) would become the feasible successor for the 10.140.0.0/24 network. To figure out, we have to compare the Advertised Distance of that route with the Feasible Distance of the successor’s route, if AD < FD then it will become the feasible successor. In this case, because AD (155160) < FD (156160) so it will become the feasible successor. Therefore we can conclude the network 10.140.0.0/24 has 1 feasible successor.

After understanding the output, let’s have a look at the entire output:

simlet_show_ip_eigrp_topology_all_links_2

Because the question asks about feasible successor so we just need to focus on entries which have more paths than the number of successor. In this case, we find 3 entries that are in blue boxes because they have only 1 successor but has 2 paths, so the last path can be the feasible successor.

By comparing the value of AD (of that route) with the FD (of successor’s route) we figure out there are 2 entries will have the feasible successor: the first and the second entry. The third entry has AD = FD (30720) so we eliminate it.

Question 2

Which three EIGRP routes will be installed for the 172.17.3.128/25 and 172.17.2.0/24 networks? (Choose three)

A – 172.17.3.128.25 [90/28160] via 172.17.1 2, 01:26:35, FastEthernet0/2
B – 172.17.3.128/25 [90/30720] via 172.17.3.2, 01:26:35, FastEthemet0/3
C – 172.17.3.128/25 [90/30720] via 172.17.10.2, 01:26:35, FastEthernet0/1
D – 172.17.2.0/24 [90/30720] via 172.17.10.2, 02:10:11, FastEthernet0/1
E – 172.17.2.0/24 [90/28160] via 172.17.10.2, 02:10:11, FastEthernet0/1
F – 172.17.2.0/24 [90/33280] via 172.17.3.2, 02:10:11, FastEthernet0/3

 

Answer: B C D

Explanation

First indicate the positions of these networks:

simlet_show_ip_eigrp_topology_all_links_3

Network 172.17.3.128/25 has 2 successors, therefore the two paths below are both successors.

Network 172.17.2.0/24 has only 1 successor, therefore the path lies right under it is the successor.

Question 3

Which three networks is the router at 172.17.10.2 directly connected to? (Choose three)

A – 172.17.0.0/30
B – 172.17.1.0/24
C – 172.17.2.0/24
D – 172.17.3.0/25
E – 172.17.3.128/25
F – 172.17.10.0/24

 

Answer: C E F

Explanation

simlet_show_ip_eigrp_topology_all_links_4

First, we should notice about the entry in the orange box, it shows that the network 172.17.10.0/24 is directly connected with this router and has a FD of 28160. So we can guess the networks that directly connected with router at 172.17.10.2 will be shown with an AD of 28160. From that, we find out 3 networks which are directly connected to the router at 172.17.10.2 (they are green underlined). The network 172.17.10.0/24 is surely directly connected to the router at 172.17.10.2 (in fact it is the network that links the router at 172.17.10.2 with Core1 router).

 

Other lab-sims on this site:

EIGRP Stub Sim

OSPF Sim

EIGRP OSPF Redistribution Sim

IPv6 OSPF Virtual Link Sim

Policy Based Routing Sim

Comments
Comment pages
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  1. mongolio
    August 18th, 2010

    >>First, we should notice about the entry in the orange box, it shows that the network 172.17.10.0/24 is directly connected with this router and has a FD of 28160. So we can guess the networks that directly connected with router at 172.17.10.2 will be shown with an AD of 28160.
    o_O
    28160 is the local router FD for connected network, how can we assert that neigboring router have identical links to local? Maybe it has serial link with bandwidth 64 kb connected, then AD will be mutch worse then 28160.
    This answer seems to be more intuitive than reasonable…

  2. digitaltut
    August 18th, 2010

    Yes, it is the most reasonable answer. It is not always correct.

  3. HG
    August 26th, 2010

    thank you mongolio explain the answer angin .so I understand well

  4. firstcause
    September 7th, 2010

    Wait, three networks ACTUALLY show “via connected” – how is it not those three?
    172.17.10.0/24 via Fa0/1
    172.17.1.0/24 via Fa0/2
    172.17.3.0/25 via Fa0/3
    Three networks directly connected to three interfaces…what am I missing here?

  5. Muhammad
    September 9th, 2010

    @firstcause :

    agree with you

  6. David
    September 19th, 2010

    @Muhammad , @firstcause :

    It says which networks are connected to 172.17.10.2, if the router that this command was run on was 172.17.10.2 then we would not be seeing routes advertised as ‘via 172.17.10.2’ such as the one to 172.17.2.0

  7. Ben Hayak
    October 7th, 2010

    mongolio & firstcause

    you can see that 172.17.10.2 directly connects to This Router (Core1)
    through fa0/1 network 172.17.10.0/24 is obvious.

    172.17.1.0/24 via Fa0/2
    172.17.3.0/25 via Fa0/3
    both directly connect from core1 to other routers but we don’t know to which routers. agree?

    FD = would be the same on shared link routers(default metrics) unless you manually change only one side(router) with a different BW or Delay.

    so you are right that it’s not 100% correct but it’s more likely answer.

  8. Miljan
    October 12th, 2010

    I check the table for entries witch have a “via 172.17.10.2” entry. if the entry isn’t first in the list (has higher AD) that means it’s not directly connected. it is highly unusual that the directly connected interface has higher AD than not directly connected.

  9. Guy
    October 19th, 2010

    Question 3 why not the answer B. 172.17.1.0/24 is not correct. pls explain

  10. Lara
    November 10th, 2010

    Good explanation Miljan!

  11. athai
    November 15th, 2010

    @ GUY,

    notice: via Fa0/2 # Fa0/1

  12. bonesaw
    December 2nd, 2010

    I didn’t get why F was an answer until I thought about the question “Which three networks is the router at 172.17.10.2 directly connected to?”

    So if the IP of the routers interface is 172.17.10.2 AND the subnet is 172.17.10.0/24 well the router MUST be directly connected.

  13. Bobby G
    December 23rd, 2010

    Question 3 asks which networks router at 172.17.10.2 is directly connected to. First, consider the output shown. The top line of the output says “IP EIGRP Topology table for AS(65001)/ID (172.17.10.1)” which indicates that we’re issuing the show command from a different router. Had the question asked which networks router 172.17.10.1 was directly connected to, the answer would be B, D, F but that’s not what is being asked. We’re asked to determine what links are connected directly to our ‘neighboring’ router 172.17.10.2. Therefor, I agree the correct answers are as listed (C,E,F).

  14. diaaa
    January 1st, 2011

    i think the answer will be A,E,F because it was mentioned that those three networks can be reached through 172.17.10.2

  15. Anonymous
    February 15th, 2011

    Question 1
    Even for the 1st entry 172.17.3.128/25 the FD(30720) > AD (28160) but still ignored, am I missing something here?

  16. dong
    February 17th, 2011

    Hi guys.
    Assuming all router have default k value.

    ***
    First, we can sure that : router 10.1 connected directly with router 10.2 via fastEthernet, metric = 28160. From formula of metric: 28160 = 256x(10.000.000/100.000 + delay) –>delay(between 10.1 and 10.2) = 10.

    ***
    Refer to “3.128 via 10.2 (30720/28160.)”,
    AD = 28160, (same at above). It could be a fastEthernet, delay =10, between 10.2 and 3.128.
    Lets check it with FD :FD = 256x(10.000.000/minimum BW + delay + delay ) = 256x(100+10+10) = 30720 !!! (Bravo!!!)

    ***
    172.17.2.0 is same as 172.17.3.128.

    I think my explain could make the answer more reasonable.

  17. san
    February 28th, 2011

    The neighbor’s advertised distance must be less than the feasible distance of the current successor so 172.17.3.2 is not right ans. In 2nd Q.

  18. sam
    March 13th, 2011

    currently any1 give the exam………

    wat type of question are asked in exam

  19. w1zard
    April 4th, 2011

    Question 3 asks:
    Which three networks is the router at 172.17.10.2 directly connected to?

    The question might as well have been:
    Which three networks is Core2 directly connected to?

    The question is not about Core1, but about the router with a router-id of 172.17.10.2 .
    The output we have here is for device Core1, so we have to deduce what networks are connected to the other router (the router with a router-id of 172.17.10.2).
    We do this by reasonably ( like dong pointed out ) assuming that when Core2 reports a RD of 28160 for a given network (networks 172.17.3.128/25 and 172.17.2.0/24 in this particular case), then these networks are directly connected to Core2.
    Now, a very bad network administrator could have easily changed the delay and bandwidth settings on interfaces connecting to networks, but that would change nothing in the answers of this question. The K values could not have been changed on just that one router, or anyway they would have to be changed everywhere, thus making no difference.

    The main reason that we know that Core2 is directly connected to those networks is because no-one, (no other router) has a feasible distance that is better than the reported distance that Core2 (the router with a router-id of 172.17.10.2) reports for those networks. Since Core2 has the lowest metric (feasible Distance) to get to those networks, then this must mean that all other routers (including the routers with router-IDs of 172.17.10.1, 172.17.3.2) use the path through Core2.

    @digitaltut

    Please fix the following:

    “So we can guess the networks that directly connected with router at 172.17.10.2 will be shown with an AD of 28160.”
    to:
    “So we can guess the networks that directly connected with router at 172.17.10.2 will be shown with a Feasible Distance (EIGRP metric) of 28160. The Administrative Distance of such connected networks will be the default of 0.”

  20. Leo from China
    April 28th, 2011

    i failed my TSHOOT exam. this OSPF questions all of them wrong and old. no questions from this one. pls change and update that questions!!!! 9tut!!!

  21. CJS
    April 30th, 2011

    HI

    Q2:
    Did I get it right that question 2 means “Which three EIGRP routes will be installed for the 172.17.3.128/25 and 172.17.2.0/24 networks INTO THE EIGRP TOPOLOGY TABLE? ” ???

    I 1rst thought it means “Which three EIGRP routes will be installed for the 172.17.3.128/25 and 172.17.2.0/24 networks INTO THE ROUTING TABLE?” !!

    If yes, the answer is clear. If no, I’ve a problem :-)

    Cheers and congrats to that great page!!
    CJS

  22. w1zard
    May 1st, 2011

    This is a simlet question. This means that the the output of the show ip eigrp topology all-links command that appears at the beginning of the page is valid and used as reference for answering all the next questions. The output of the show ip eigrp topology all-links command gives you the networks, their next hop, the next hop’s Reported Distance, and the Feasible Distance to reach that network as learned by the EIGRP process. Question number two (Q2) apparently asks which routes will be installed into the ROUTING table. This we can tell by listening to four hints:
    1. The EIGRP topology table is already given to us at the beginning of the Simlet question.
    2. The format of the possible answers is the format of routes in the ROUTING table.
    3. The EIGRP topology table is built using discovered networks, and all networks learned via EIGRP are present in the EIGRP topology table. (there are no criteria regarding Distances etc.)
    4. The EIGRP topology table (and EIGRP as a protocol for that matter) has no concept of Administrative distances, which are present in the possible answers that we are presented with.

  23. pokey
    May 5th, 2011

    hi, pls can any one send me the link to download the lab sims for 642 902{routing} so that i can practice them or send it to my email …tunde4real055@yahoo.com

  24. Mike
    May 8th, 2011

    @W1zard
    Very good! I might add a comment about using the FD (28160) of the neighboring router. To make a determination as to whether a route is directly connected or not. From the perspective of the neighboring router (172.17.10.2) a directly connected network will have an FD of 0 so the total distance to the Core1 router will be 0+28160. So, any network with a path that has an AD equal to the FD of 172.17.10.2 is directly connected to it. That applies in all equal cases. Further, looking at the topology table again. If there is 1 successor and 2 paths then the first path is the successor path and the other is not a Feasible Successor. If there are 2 successors and 2 or more paths the two paths will be first the Successor, then the Feasible Successor and both will be put in the routing table.
    If there are more paths, for example, 2 successors and 4 paths, the first will be the successor (always), the second will be the Feasible Successor(always if there is one), then followed by non-feasible successor paths in that order.

  25. CJS
    May 11th, 2011

    @w1zard:

    Thanks for that great answer. Of course u r absolutely right!
    To tell the truth I do not know why this was not clear to me that day!?!?! Right now I don’t understand why I aksed that silly question!

    thx again and best regard

  26. DaEngineer
    May 24th, 2011

    Does anyone know where I can get premade topology for GNS3 for labs for this exam ? I figure someone must have created and uploaded these, can’t find them on didgitaltut

  27. YESUAH
    May 28th, 2011

    preparing 2 right 642-902 any help mail to yesuah1@gmail.com thks

  28. Azim
    June 5th, 2011

    Can anyone give me the answer of P4S v4.11 question number 14 of EIGRP, from my understanding it could be 5 but answer shows 3,

    confused

  29. JHUN
    June 9th, 2011

    DO U HAVE THE LATEST CCNP PASS4 SURE? CAN I HAVE IT? NEED TO TAKE THE EXAM IN A WEEK

  30. Anonymous
    June 16th, 2011

    @9tut

    Question 1 is totally wrong…

    the correct answers are C and E

    the FD metric parameter for the network line of the routes is all you need to go by to answer this question… of all the routes 2 of them have a FD of 30720 (which is the lowest).

    on 172.17.3.128 both routes meet the feasibility parameter so it has 2 successors.

    on 172.17.2.0 the route with the lowest FD 172.17.10.2 also meets the feasibility criteria as its AD is lower then 30720.

    i had to really study wendell odoms icnd 2 book to understand this and i think i finally get it. this is a tough concept but the thing to remember is the FD metric for the network line is what you look at first. this question is worded so that all you need is the FD metric on the very first line to answer it.

  31. Anonymous
    June 16th, 2011

    each network has 1 successor with the first network having 2. a successor simply means that a route has a AD lower then the FD of the network. this does not qualify it as a feasible successor.

    feasible successors are determined firstly by which network has the lowest FD. in this example there are 2 networks that match for lowest (30720). of those networks there are three routes that meet the feasible successor criteria.

  32. Anonymous
    June 16th, 2011

    i am going to re-read wendell odom to make sure i am right but if i am then that totally changes the answer for Q3 too.

    i dont understand that question… how do you know it is directly connected to those networks… if it is via anything then it isnt directly connected right?

    wouldnt the three directly connected networks be the ones without routes?? B, D, F

  33. Anonymous
    June 16th, 2011

    I think i got it… the feasible successors are only used if the connected routes go down. if you look at it this way it all makes sense.

    the directly connected routes are the ones with the lowest metric (28160) and no routes.

    the feasible successors are the routes that have an AD lower then the next lowest metric which is 30720

  34. Anonymous
    June 16th, 2011

    geez this is complicated… i think i am wrong on Q3.. i get that one now. i am still not sure about Q1 though. that one doesnt seem to jive with what i have seen. i will study more tonight the ICND 2 book to make sure

  35. blah, blah and more blah
    June 17th, 2011

    @9tut

    Ok i know what the problem is now. U are right here on this page. All the questions here are correct it’s the question 4 on the other page (EIGRP questions) that is screwed up. That question is totally messed up and has been screwing me up bad. There are no feasible successor routes in the output for that question.

    There are two rules for this from what i have seen. According to Wendell Odom.

    1 The feasible successor must not be a successor route. (ref 386 ICND 2)

    2 The Reported Distance (or AD as you have been calling it) must be less then the feasible distance. Period. (ref. 395 ICND 2)

    It doesn’t say less then or equal too… it must be less or it’s not a feasible successor. If a route fails and there is no feasible successor then EIGRP uses DUAL to query for a loop free route to replace the failed route. All the Feasible Successors on Question 4 from the other page have RD’s that are equal to the FD of the successor. That question has typos or something… i would not expect to see that on a Cisco exam.

    Something else that was very confusing for me was highlighting the FD of the successor route without explaining how it relates to the FD of the network. They are one in the same. The FD of the successor route is what generates the FD for the Network.

  36. shah
    July 2nd, 2011

    Hello guys..

    does anyone have ccnp route 642-902 cbt, pass4sure or any dumps. kindly send me links on shariq2009@live.com or u can send here as well.

    Thanksss

  37. Newbie4@Digitaltut
    July 3rd, 2011

    Hi, in Q1. why the answer E is not correct . E also has its AD lower than its FD so it should be a feasible successor also right ?

  38. shah
    July 3rd, 2011

    Hello guys..

    does anyone has ccnp route 642-902 cbt, pass4sure any dumps or GNS3 LAB?.
    kindly send me links on
    shariq2009@live.com or u can send here as well.

    GNS3 LAB is very important.. kindly send me links.

    Thanksss

  39. digitaltut
    July 23rd, 2011

    @Newbie4: Sorry for my late response, E is not correct because the network 172.17.3.128/25 has 2 successors and it doesn’t have any feasible successor.

  40. Panama foundation
    August 1st, 2011

    .DUAL evaluates the data received from other routers in the topology table and calculates the primary successor and secondary feasible successor routes. Both successors and feasible successors are maintained in the topology table but only the successors are added to the routing table and used to route packets..For a route to become a feasible successor its RD must be smaller than the FD of the successor.

  41. @ Ashish
    August 9th, 2011

    I have confusion in question no. 2, why option D is write and E can also be the right answer, please correct me if i am wrong?

  42. mettl
    August 10th, 2011

    @ Ashish

    D – 172.17.2.0/24 [90/30720] via 172.17.10.2, 02:10:11, FastEthernet0/1
    E – 172.17.2.0/24 [90/28160] via 172.17.10.2, 02:10:11. FastEthernet0/1

    The correct metric is 30720.
    28160 is the AD, it appears in the topology table, never in the routing table

    So, answer E in wrong

  43. anon
    August 19th, 2011

    anybody know if this is current?

  44. Madjheed
    September 3rd, 2011

    Pls, add more questions 4 good practice…..

  45. Paulie
    September 7th, 2011

    Can someone please send me GNS3 labs please send to paulina.tsengiwe@gmail.com

  46. Sugel
    September 16th, 2011

    It chooses the path through One as its best path the successor and the path through Three as a loop-free path a feasible successor . When the path through Router One becomes unavailable Router Two examines its topology table and finding a feasible successor begins using the path through Three immediately..From this brief explanation it is apparent that EIGRP must provide . A feasible successor is a path whose reported distance is less than the feasible distance current best path .

  47. Bruno
    September 26th, 2011

    Do we really need so many areas?????!!!!! 4294967295?????

  48. Asterisk
    October 1st, 2011

    Please find below links to a GNS3 LAB I’ve made to simulate the EIGRP Simlet.
    This can help to a better understanding of the Simlet.

    http://www.4shared.com/photo/alEsWfkq/EIGRP_Simlet.html
    http://www.4shared.com/document/koUhXzxq/R_Fa01.html
    http://www.4shared.com/document/T9Ab90vd/R_Fa02.html
    http://www.4shared.com/document/x81TT_qV/R_Fa03.html
    http://www.4shared.com/document/jwBYdfYe/Core1.html

    Real outputs from the LAB:
    * Please note the Interface References:
    Fa0/1 = Fa0/0
    Fa0/2 = Fa1/0
    Fa0/3 = Fa2/0

    Core1#show ip eigrp topology all-links
    IP-EIGRP Topology Table for AS(65001)/ID(172.17.10.1)
    Codes: P – Passive, A – Active, U – Update, Q – Query, R – Reply,
    r – reply Status, s – sia Status

    P 172.17.3.128/25, 2 successors, FD is 30720, serno 8
    via 172.17.3.2 (30720/28160), FastEthernet2/0
    via 172.17.10.2 (30720/28160), FastEthernet0/0
    P 10.140.0.0/24, 1 successors, FD is 156160, serno 6
    via 172.17.3.2 (156160/128256), FastEthernet2/0
    via 172.17.10.2 (158720/156160), FastEthernet0/0
    P 172.17.10.0/24, 1 successors, FD is 28160, serno 1
    via Connected, FastEthernet0/0
    P 172.17.1.0/24, 1 successors, FD is 28160, serno 2
    via Connected, FastEthernet1/0
    P 172.17.0.0/30, 1 successors, FD is 20514560, serno 7
    via 172.17.1.1 (20514560/20512000), FastEthernet1/0
    via 172.17.10.2 (20516096/20513536), FastEthernet0/0
    P 172.17.3.0/25, 1 successors, FD is 28160, serno 3
    via Connected, FastEthernet2/0
    P 172.17.2.0/24, 1 successors, FD is 30720, serno 17
    via 172.17.10.2 (30720/28160), FastEthernet0/0
    via 172.17.3.2 (33280/30720), FastEthernet2/0

    Core1#show ip eigrp topology
    IP-EIGRP Topology Table for AS(65001)/ID(172.17.10.1)
    Codes: P – Passive, A – Active, U – Update, Q – Query, R – Reply,
    r – reply Status, s – sia Status

    P 172.17.3.128/25, 2 successors, FD is 30720
    via 172.17.3.2 (30720/28160), FastEthernet2/0
    via 172.17.10.2 (30720/28160), FastEthernet0/0
    P 10.140.0.0/24, 1 successors, FD is 156160
    via 172.17.3.2 (156160/128256), FastEthernet2/0
    P 172.17.10.0/24, 1 successors, FD is 28160
    via Connected, FastEthernet0/0
    P 172.17.1.0/24, 1 successors, FD is 28160
    via Connected, FastEthernet1/0
    P 172.17.0.0/30, 1 successors, FD is 20514560
    via 172.17.1.1 (20514560/20512000), FastEthernet1/0
    via 172.17.10.2 (20516096/20513536), FastEthernet0/0
    P 172.17.3.0/25, 1 successors, FD is 28160
    via Connected, FastEthernet2/0
    P 172.17.2.0/24, 1 successors, FD is 30720
    via 172.17.10.2 (30720/28160), FastEthernet0/0

    Core1#sh ip eigrp neighbors
    IP-EIGRP neighbors for process 65001
    H Address Interface Hold Uptime SRTT RTO Q Seq
    (sec) (ms) Cnt Num
    2 172.17.10.2 Fa0/0 10 00:43:05 74 666 0 37
    1 172.17.1.1 Fa1/0 14 00:43:06 273 1638 0 20
    0 172.17.3.2 Fa2/0 11 00:43:06 335 2010 0 19

  49. Asterisk
    October 1st, 2011

    Here is the IP Routing Table:

    Core1#show ip route
    Codes: C – connected, S – static, R – RIP, M – mobile, B – BGP
    D – EIGRP, EX – EIGRP external, O – OSPF, IA – OSPF inter area
    N1 – OSPF NSSA external type 1, N2 – OSPF NSSA external type 2
    E1 – OSPF external type 1, E2 – OSPF external type 2
    i – IS-IS, su – IS-IS summary, L1 – IS-IS level-1, L2 – IS-IS level-2
    ia – IS-IS inter area, * – candidate default, U – per-user static route
    o – ODR, P – periodic downloaded static route

    Gateway of last resort is not set

    172.17.0.0/16 is variably subnetted, 6 subnets, 3 masks
    D 172.17.3.128/25 [90/30720] via 172.17.10.2, 00:52:10, FastEthernet0/0
    [90/30720] via 172.17.3.2, 00:52:10, FastEthernet2/0
    C 172.17.10.0/24 is directly connected, FastEthernet0/0
    C 172.17.1.0/24 is directly connected, FastEthernet1/0
    D 172.17.0.0/30 [90/20514560] via 172.17.1.1, 00:52:10, FastEthernet1/0
    C 172.17.3.0/25 is directly connected, FastEthernet2/0
    D 172.17.2.0/24 [90/30720] via 172.17.10.2, 00:44:17, FastEthernet0/0
    10.0.0.0/24 is subnetted, 1 subnets
    D 10.140.0.0 [90/156160] via 172.17.3.2, 00:52:09, FastEthernet2/0

  50. Blackhat
    October 14th, 2011

    I understand the answers in question 3. However, in a real world environment, doesn’t the topology table show only successors and feasable successors? So if there are more than one route to a location in the topology table they are either all successors or one is a successor and the others are feasible successors

  51. prce
    October 16th, 2011

    The issued command on Core1 is

    sh ip eigrp topology all-links

    With the “all-links” keyword the command lists all known paths to a given subnet, not only the successors and feasible successors.

  52. Nitin Mohan
    December 6th, 2011

    Q3:
    if they are connected to the same router their FD should match, therefore the correct answer to Q3 is D,B,F i.e they have same FD 28160

  53. Da
    December 9th, 2011

    Actually their Advertised Distances should match. The Advertised Distance is the distance between the next router to the network. The Feasible Distance is the distance between me and the guy with the AD, and from him to the network. So it’s the entire distance whereas the AD is just from the next guy to the network. So where ever 172.17.10.2 is in the table, if his AD is 28160, that’s the network he is directly connected to. It is very confusing at first, but after looking at it for a while, it starts to make sense.

  54. Asif205
    December 18th, 2011

    can some one share .VCI software.

    tanh123@live.com

  55. Anonymous
    December 19th, 2011

    Don not understand. In P4S answers given are: B D F
    172.17.10.0/24 via Fa0/1
    172.17.1.0/24 via Fa0/2
    172.17.3.0/25 via Fa0/3

    What is the right answers for the exam ???

  56. Mostafa Hijazi
    December 20th, 2011

    Hello. I understand the concept about choosing Feasible successors. But in Question 1, why the route to 172.17.3.128/25 via 172.17.3.2 is not considered a Feasible successor ? The AD is less than the FD of the successor. it is because the question asked about which 2 networks has only 1 sucessor ?

    Thanks and regards,
    Mostafa Hijazi

  57. Swati
    December 23rd, 2011

    @Anonymous
    Q1
    Because the question asks about feasible successor so we just need to focus on entries which have more paths than the number of successor. In this case, we find 3 entries that are in blue boxes because they have only 1 successor but has 2 paths, so the last path can be the feasible successor.

    By comparing the value of AD (of that route) with the FD (of successor’s route) we figure out there are 2 entries will have the feasible successor: the first and the second entry. The third entry has AD = FD (30720) so we eliminate it.

  58. VED
    December 29th, 2011

    Hi All

    I passed the exam today !!! Many of You know Me Last time When I passed The CCNA exam I remember All the Question and i send to you all also and its very helpfull to U all !!! Dont Worry Friends this time Also I remember All the Question !!! In exam I got 50 question

    Out of that three are Similator
    2 drag and drop

    Friends Any one Want the Question Please Update the Mail Id Or Send the Mail to the mail id : dononearth0@gmail.com ( as u know )

    Better U send the Mail So that I can Quick reply to You All

    Help other God will help You !!!

    Ur Friend Ved Prakash INDIA

  59. B.
    January 2nd, 2012

    Hi Ved Congrats!!! I emailed you, yes pl kindly share your doc with me! :)
    Thanks and congrats again

  60. Ahmed
    January 7th, 2012

    Ved is a spammer;beware

  61. anonymous
    January 14th, 2012

    This was NOT on my test

  62. Sir CCNP
    January 18th, 2012

    Hello Friends,

    I just started to study the ROUTE test after taking almost two years off from passing the CCNA. I am planning to take the ROUTE test in two months. Are the Sims, Drag and Drop, Questions, and everything else on this site still valid for the ROUTE test?

    Thank you all!

  63. ACE
    March 3rd, 2012

    I just came back from taking the 640-802 and I passed!! 947!! I worked on the sims for a couple of hours today. I think I should’ve spent more time on them so that I could be much quicker and more confident in my execution of them. I used up a lot of time just going over things and I just finished the exam with just a minute to spare. Whewww….that was a close one. Thanks tut and everyone that has contributed to this web site. I saw the EIGRP SIM, ACL2, and the VTP sim…Tab works….but the show logging doesn’t work :( but you can ping on your router to verify if your solution to EIGRP works and when you configure the correct AS in the router the logging interrupts your typing telling you the adjacencies have formed. I did not get any questions on which route is the feasible successor, thank God!!! Good luck to everyone and thanks Tut and digitaltut for this incredible site. :)

  64. OZ-1
    March 20th, 2012

    Guys don not buy any CISCO Q- A from examworx nad test king , etc- they are all cheaters !!!

  65. Info
    April 5th, 2012

    Passed today with 1000/1000. Wheelman still valid. Got four Sims Virtual Link, Eigrp-Ospf Redistribution, OSPF Stub and PBR. There were few changes with IP addresses/process ID’s. Once you notice those little things you get away easily.

    The telnet for me didn’t work in the redistribution sim but I still got full marks.
    Apart from sims all the other ques were exactly the same as they are in Wheelman.

    For guys who have time, I would like to suggest to read through this site “http://www.scribd.com/doc/35949708/Cisco-CCNP-ROUTE-642-902-Actual-Test” as well. I found this one the night before and got freaked out as there were many new ques. But its good that I dint get any unusual ques.

    All the best

  66. Kaushik
    April 6th, 2012

    To info thank you very much. I am planning to appear next week for the Route exams.

  67. Ishmail
    June 27th, 2012

    i will be writing next month

  68. Anonymous
    June 27th, 2012

    Q1 can’t be right. Based on the explanation (and on the feasibility condition), answers A, E, and F are all correct, as all of these routes have one successor, two paths, and the last path has an AD less than the FD of the successor.

  69. Swede
    July 2nd, 2012

    Anonymous, otice that both paths for 172.17.3.128/25 are SUCCESSORS (doing equal-cost load-balancing).

  70. Kishore
    July 31st, 2012

    Got MY CCNP Route today with 1000/1000….

    Wheelman dumps and Digitut labs are 100% valid….
    Thanks for the help… You guyz Rock…

    Simulations::
    OSPF Virtual Links
    EIGRP and OSPF Redistribution
    OSFP Stub simulation
    Policy Based Routing

    Careful on Multiple choice questions in the exam. ,
    all the Options were well shuffled….

    Good Luck Boyzzzzzz

  71. souljar’s
    August 2nd, 2012

    preparing 2 right 642-902 any help, with the latest questions, E-Mail sollymojela@yahoo.com

  72. Steve in Illinois
    August 5th, 2012

    I remain confused by Q3. Thinking it out, if not for the directed connection I were to think of how I recognize a network connected to an adjacent node I would have to say they would all have the same FD-AD (NOT the same AD) and that difference would be the FD for the network to the adjacent node. In the configuration shown A,C and E have an FD-AD of 2560. Unfortunately the connected network to the router in question is 28160.
    I guess i will reread the thread and try to devine the Cisco intent.

  73. CCNP_USA
    August 19th, 2012

    I passed my ROUTE exam on Friday 17/08 completing my CCNP certification. My overall score today was 91%. Without studying really hard and some real world experience, I would not have passed this exam. It is very tough and detailed.

    *****************************************************************************

    Materials used for this exam:

    Cisco CCNP Route official Certification Guide by Wendell Odom
    http://www.amazon.com/ROUTE-642-902-Official-Certification-Guide/dp/1587202530
    There are some excellent questions in the book that can prepare you for the exam.

    Digital Tut – I studied the whole website
    http://www.digitaltut.com

    I practised on GNS3 using the following labs
    http://www.4shared.com/file/MNxMccev/GNS3_642-902_Test_Sims.html

    Wheelman Exam dumps – I studied all questions
    http://www.examcollection.com/642-902.html

    *****************************************************************************

    Labs on digitaltut are similar, but in the exam they are slightly different.
    Enough so that anyone memorising and not understanding will not pass.

    copy run start did not work in any SIM
    the ‘?’ was available during sims

    PBR SIM
    Exactly to what appears on
    http://www.digitaltut.com/route-policy-based-routing-sim
    Include the route-map pbr permit 20 if you want to win!

    IPv6 OSPF Virtual-link Sim
    Similar, but with a trist
    http://www.digitaltut.com/route-ipv6-ospf-virtual-link-sim

    OSPF stub SIM
    Similar, but again with a twist
    http://www.digitaltut.com/route-ospf-sim

    EIGRP OSPF redistribution
    Different IPs, routers and areas.
    Concept the same.
    I did have two FastEthernet links so under the eigrp process on R2 “distance eigrp 90 109” was required
    http://www.digitaltut.com/route-eigrp-ospf-redistribution-sim

    *****************************************************************************

    Four or so questions were not from Wheelman exam dumps, but they were similar enough.

    I wish everyone the best of luck.
    Oh – and don’t forget to DONATE to digitaltut.com

  74. klauss
    September 9th, 2012

    9tut,

    The answer below was given to Ashish. i still disagree. Would you please share some light?
    I think E should have been the answer.

    @ Ashish

    D – 172.17.2.0/24 [90/30720] via 172.17.10.2, 02:10:11, FastEthernet0/1
    E – 172.17.2.0/24 [90/28160] via 172.17.10.2, 02:10:11. FastEthernet0/1

    The correct metric is 30720.
    28160 is the AD, it appears in the topology table, never in the routing table

    So, answer E in wrong

  75. travis
    September 20th, 2012

    It is easiest if you draw out the question. Place 2 routers, one will be 172.17.10.1 = A and the other will be 172.17.10.2 =B

    A – – – – B

    Now, A reports a FD to Router B as 28160. This means that the distance From Router A to Router B is 28160. This means that any DIRECTLY CONNECTED routes on B will have an Advertised Distance of whatever the Distance from A to B is… which is 28160.

  76. boyi
    October 11th, 2012

    are the same questions in real exam for this simlet?
    any change? same ip address etc.

    Thanks!

  77. GOR
    October 17th, 2012

    Q3. CEF is true if all interfaces on routers FastEthernet.
    But if router 172.17.10.2 have Serial interface(bw 1544, delay 2000), AD from him will be 2169856, and network also will connected to.

  78. IceBlue
    November 13th, 2012

    Which two networks does the Core1 device have feasible successors for? (Choose two)

    pass4Sure states the answer is A & E. Digitaltut is A & F – which is it?!?!?!

  79. Kong
    November 21st, 2012

    @IceBlue:

    pass4sure is clearly wrong, because answer E – 172.17.3.128/25 if you check in the topology table, both routes are successors as it shows 2 successors. So there’s no Feasible Sucessor for 172.17.3.128/25.

    So A & F is correct.

  80. mircx
    November 21st, 2012

    Q3 is a bit tricky and answers are correct.

    But the logic is a bit different.
    Remember the question is what are the directly connected networks of the neighbor router (let’s called it R2), not the router on which the command was executed (R1)

    Like stated in the answer, begin with noticing the directly connected network who is in the same subnet as the two routers’ provided ip addreses. This is obviously the first connected network.

    The listed FD for this network and the comparison between FD and RD’s is irrelevant though in finding the other connected networks and i’ll explain why.

    If the networks connected to R2 are of other type/speed than the network between R1 and R2 (who is a FE) they will have a different metric in EIGRP and the rule FD=AD is no longer valid.

    Instead, the logic of finding directly connected routes to R2 should be:
    “RD of the routes listed with 172.17.10.2 as next-hop should have a default metric value for the respective interface type directly connected ” (ex. FE = 28160)
    More than that, all entries in the output would have to be checked , not only those for who 172.17.10.2 is a successor.

    True, if R2 has only fast ethernet directly connected networks (i.e. same interface type as the one connecting R1 to R2) the rule FD=AD stands. But in all other cases it’s wrong.

    Consider the following example:

    R1 (10.0.2.1) connects to R2 (10.0.2.2) with FE and both are in EIGRP

    R1#show ip eigrp topology all-links
    P 10.0.2.0/24, 1 successors, FD is 28160
    via Connected, FastEthernet0/0
    P 10.0.3.0/24, 1 successors, FD is 30720
    via 10.0.2.2 (30720/28160), FastEthernet0/0
    P 10.0.4.0/24, 1 successors, FD is 20514560
    via 10.0.2.2 (20514560/20512000), FastEthernet0/0
    P 10.0.5.0/24, 1 successors, FD is 284160
    via 10.0.2.2 (284160/281600), FastEthernet0/0

    Which networks are connected to R2?
    By the rule FD=AD only 10.0.3.0 is connected but it’s no true.

    In fact all networks are directly connected to R2:
    10.0.2.0 is FE (direct link, default 28160)
    10.0.3.0 is FE (default 28160)
    10.0.4.0 is serial T1 (default 20512000)
    10.0.5.0 is Ethernet (default 281600)

  81. Kong
    November 22nd, 2012

    Didn’t encounter this sims in my exams. Other than that everything on this website is still valid and very good study materials as of today.

    “Cisco CertifyMe 642-902 v2012-09-11 by Johannes 391q.vce” questions also still valid and very good practise materials.

    Good Luck!

  82. Tomorrow
    November 22nd, 2012

    On question 3:
    1) The question is not asking what is connected to this router. I made that mistake initially
    2) By the IP address in the question the router being asked about must be connected to fa0/1 on the router we are viewing output on. So one of the three networks is 172.17.10.0/24
    3) Then just look for entries in the output that say “via FastEthernet0/1”
    4) From that selection choose the lowest ADs: 172.17.2.0/24 and 172.17.3.0/24 as they are bound to be the closest to the router in question

    That was my logic anyway

  83. tut99
    January 15th, 2013

    anybody else is working through Q3?
    answer showed here is C,E,F, it seems logic to me.
    PSS4S shows B, D,F
    any thoughts?
    thanks.

  84. Klauss_21
    February 1st, 2013

    Question 2 answers should be B C E, in my opinion.

  85. shivam
    February 3rd, 2013

    Are these labs including this still valid. i am gonna appear in exam this week.
    Any one who see this comment who has given exam recently please reply
    regards

  86. daniel
    February 6th, 2013

    Hi all,

    please share the correct answers to Q1….

    Thanks

  87. StudyMan
    February 25th, 2013

    @daniel

    The answer is there in plain text. Read it.

  88. Prabhat
    March 11th, 2013

    Hi All,

    Passed CCNP Routing on 8th March with 965 marks…. Able to complete this within 5 days (studied after office hours).. Thanks to Digitaltut and Dumps from Peter (636 Qstns). Thank you guys for posting your valuable comments and all the guidance.

    All the qstns and SIMs were same and still valid. I didnt practice SIMs hence got struck in redistribution SIM.

    Thank you guys once again for guys for giving me confidence, great job!!!!

  89. Ghost from Germany
    April 4th, 2013

    Hi All,
    I took the exam last week with max score.
    Not this EIGRP Simlet, not OSPF Hotspot.
    The other 5 configuration labs are present in the exam and valid.
    Don’t worry if you can’t do a ‘copy run start’ in the real exam (type it and good).
    Ip addresses, names, areas and processes can change!
    Don’t type blind!!! Know the concept and the commands!!!
    And you are on the safe side.
    Thanks digitaltut, Boyi n Peter (All question from these only).

  90. rock
    April 6th, 2013

    hi ghost have you latest dumps s please send me

  91. J from NZ
    April 9th, 2013

    Im still puzzle with Q3,

    I think the ans should be A,C,E. My logic is below

    R1 (172.17.10.1) ———————- R2 (172.17.10.2)

    1. With the current eigrp topology showning from R1 and not R2. So all the directly connect interface on R1 cannot be on R2. Hence this eliminated B,D,F correct me here if I’m wrong
    2. So all the possible network that can be via 172.17.10.2 is (showing on eigrp top via 172.17.10.2)

    172.17.0.0/30 —> via 172.17.10.2 –> A
    10.140.0.0/24 —-> via 172.17.10.2
    172.17.2.0/24 —-> via 172.17.10.2 —> C
    172.17.3.128/25 —-> via 172.17.10.2 —> E

    Question 3

    Which three networks is the router at 172.17.10.2 directly connected to? (Choose three)

    A – 172.17.0.0/30
    B – 172.17.1.0/24
    C – 172.17.2.0/24
    D – 172.17.3.0/25
    E – 172.17.3.128/25
    F – 172.17.10.0/24

  92. Did_it_work?
    April 11th, 2013

    J from NZ says “So all the directly connectED interfaceS on R1 cannot be on R2 ”

    Why is that?
    What’s about Core1:Fa0/1?

    It is directly connected on R1(Core1) AND(!) R2 on the network 172.17.10.0/24.

    :)

  93. ekta
    April 18th, 2013

    Hi ..can anyone share the VCE software
    ekta15_80@yahoo.co.in

  94. ekta
    April 19th, 2013

    can anybody tell me ..
    can i take the CCNP route without having valid CCNA VOICE.

  95. patrik
    April 19th, 2013
  96. Hani
    April 19th, 2013

    Yes Ekta you can… if u have a valid CCNA.

  97. Raj
    April 22nd, 2013

    Can someone explain to me why in question 3 why is ‘A’ not one of the right answers?

    Question asks “which three networks is the router at 172.17.10.2 directly connected to” and in the script we clearly see

    P 172.17.0.0/30, 1 successors, FD is 20514560, serno 7
    via 172.17.1.1 (20514560/20512000), FastEthernet1/0
    via 172.17.10.2 (20516096/20513536), FastEthernet0/0

    Making A also a possible answer. Why is is not a possible answer?

  98. Yassine
    April 26th, 2013

    in question 3 28160 is the AD for the other networks not the FD !!! the explanation is confusing

  99. New_Student
    May 3rd, 2013

    @Yassine,

    The path right below is the successor and is the one to be installed in the routing table. It has an FD = 30720 and AD = 21600. The other path does not meet the feasibility condition. It cannot even be used as a feasible successor – so, forget about installing it in the routing table.
    Got it?

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